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What is the value of 1/(1×2) + 1/(2×3) + 1/(3×4) + … + 1/(19×20)?

1659Medium DSSSB TGT Computer Science 0 replies 1 views
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What is the value of 1/(1×2) + 1/(2×3) + 1/(3×4) + … + 1/(19×20)?

  • A19/20
  • B18/19
  • C20/21
  • D9/10
Correct answer: A

Explanation

Each term 1/(n(n+1)) = 1/n − 1/(n+1), so the sum telescopes to 1 − 1/20 = 19/20.

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