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If a wire conductor of 0.2-ohm resistance is doubled in length, its resistance becomes
- A0.4 ohm
- B0.8 ohm
- C0.6 ohm
- D1.2 ohm
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0
CCommunity
Given that resistance of a conductor = 0.2 Ω
We know that resistance of a conductor is given by
$(R = \frac{{\rho l}}{A})$
Where ρ is resistivity
l is length
A is cross-sectional area
Given that, the length becomes double
The new resistance will become twice of the previous.
New resistance = 2 × 0.2 = 0.4 Ω
We know that resistance of a conductor is given by
$(R = \frac{{\rho l}}{A})$
Where ρ is resistivity
l is length
A is cross-sectional area
Given that, the length becomes double
The new resistance will become twice of the previous.
New resistance = 2 × 0.2 = 0.4 Ω
0
CCommunity
2 × 0.2 = 0.4 Ω