Question discussion

If 50 less had applied and 25 less selected, the ratio of selected to unselected would have been 9 : 4. How many candidates had applied, if…

192773Medium 2 replies 2,920 views
34
If 50 less had applied and 25 less selected, the ratio of selected to unselected would have been 9 : 4. How many candidates had applied, if the ratio of selected to unselected was 2 : 1?
  • A125
  • B250
  • C375
  • D500
Answer not set
0
CCommunity
Since the ratio of selected to unselected was 2 : 1;

Selected candidates = 2x, Unselected candidates = x and total applied candidates = 3x

If 50 less had applied and 25 less selected, the ratio of selected to unselected would have been 9 : 4

∴ Total applied candidates = (3x – 50)

And Selected candidates = (2x – 25) and Unselected candidates = x – 50 + 25

∴ (2x – 25) / (x – 25) = 9/4

⇒ x = 125

∴ Total number of candidates who applied = 3x = 375
0
CCommunity
Number of total candidates is 210.

Step-by-step explanation:

Your question needs a correction.

Correction : The ratio of selected would have been 9 : 5, if 50 less had applied and 25 less selected.

If this is not that correction, and your question is correct. It is not mentioned whether 50 less candidates who applied are lesser than the total candidates or than the original number of candidates, and similarly with the number of selected candidates. So, this question is incomplete or whole information is not provided.

Case 1 : If question is incorrect :

It is given that the ratio of selected to unselected was 2 : 1 .

Let the number of selected candidates be 2a and number of unselected candidates be a.

Therefore,

= > number of total candidates equal to selected candidates + and unselected candidates

= > number of total candidates = 2a + a

= > number of total candidates = 3a

According to the question :

If 50 less had applied and 25 less selected, the ratio of selected to unselected would have been 9 : 4.

If 50 less had applied then the number of total candidates who applied = number of total candidates - 50 = 3a - 50

If 25 less had selected then the number of total candidates who had got selected = 3a - 50 - 25 = 3a - 75

Therefore,

the number of candidates who were not selected = the total candidates - number of candidates who had got selected = 3a - ( 3a - 75 ) = 3a - 3a + 75 = 75

As given in question : If the above condition would happen , then the ratio would have been 9 : 5.

= > ( 3a - 75 ) : 75 = 9 : 5

= > 3a - 75 = ( 9 x 75 ) : 5

= > 3a - 75 = ( 9 x 15 )

= > 3a = 135 + 75

= > 3a = 210

Hence the number of total candidates is 210.

Case 2 : If things are not mentioned properly :

It is given that the ratio of selected to unselected was 2 : 1 .

Let the number of selected candidates be 2a and number of unselected candidates be a.

Therefore,

= > number of total candidates equal to selected candidates + and unselected candidates

= > number of total candidates = 2a + a

= > number of total candidates = 3a

According to the question :

If 50 less had applied and 25 less selected, the ratio of selected to unselected would have been 9 : 4.

If 50 less had applied then the number of candidates= original number of total candidates who applied - 50 = 3a - 50

If 25 less had selected then the number of total candidates who had got selected = original number of selected candidates - 25 = 2a - 25

Therefore,

the number of candidates who were not selected = the total candidates - number of candidates who had got selected = 3a - 50 - ( 2a - 25 ) = a - 25

As given in question : If the above condition would happen , then the ratio would have been 9 : 4

= > ( 2a - 25 ) : ( a - 25 ) = 9 : 4

= > 8( 2a - 25 ) = 9( a - 25 )

= > 8a - 100 = 9a - 225

= > 225 - 100 = 9a - 8a

= > 125 = a

Hence the number of total candidates is 3 x 125 i.e. 375 .