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If 4 men or 6 boys can finish a work in 20 days. How long will 6 men and 11 boys take to finish the same work?
- A4 days
- B5 days
- C6 days
- D7 days
Answer not set
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0
CCommunity
⇒ Given: 4 men = 6 boys
⇒ Then, 1 boy = 4/6 men = 2/3 men
⇒ 11 boys = 2/3 × 11 men = 22/3 men
⇒ Then, 6 men + 11 boys = 6 + (22/3) = 40/3 men
⇒ 1 work done = 4 men × 20 days
⇒ Now, let time taken to finish the same work be d
⇒ Then,
⇒ 4 × 20 = 40/3 × d days
⇒ 4d × 20 × 3/40
∴ d = 6 days
⇒ Then, 1 boy = 4/6 men = 2/3 men
⇒ 11 boys = 2/3 × 11 men = 22/3 men
⇒ Then, 6 men + 11 boys = 6 + (22/3) = 40/3 men
⇒ 1 work done = 4 men × 20 days
⇒ Now, let time taken to finish the same work be d
⇒ Then,
⇒ 4 × 20 = 40/3 × d days
⇒ 4d × 20 × 3/40
∴ d = 6 days
0
CCommunity
6 days