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A’s age is 1/6 of B’s age. B’s age will be twice of C’s age after 10 years. If C’s eighth birthday was celebrated two years ago, then the present age of A must be
- A5 years
- B10 years
- C15 years
- D20 years
Answer not set
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0
CCommunity
C’s 8th birthday was celebrated 2 years ago
Thus C’s present age is 10 years
Let B’s present age be ‘x’ years
x + 10 = 2 × (10 + 10)
∴ x + 10 = 40
∴ x = 30
A’s age is 1/6th of B’s age
Thus A’s present age is 5 years
Thus C’s present age is 10 years
Let B’s present age be ‘x’ years
x + 10 = 2 × (10 + 10)
∴ x + 10 = 40
∴ x = 30
A’s age is 1/6th of B’s age
Thus A’s present age is 5 years
0
CCommunity
5 years is the correct Answer.