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From the table x = 1, 2, 3 and y = 1, 4, 9, the value of y at x = 1.5 obtained from Newton's forward-difference interpolation formula is

2101Medium DSSSB TGT Computer Science 0 replies 1 views
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From the table x = 1, 2, 3 and y = 1, 4, 9, the value of y at x = 1.5 obtained from Newton's forward-difference interpolation formula is

  • A2.00
  • B2.25
  • C2.50
  • D2.75
Correct answer: B

Explanation

With p = 0.5, Δy₀ = 3 and Δ²y₀ = 2: y = 1 + 0.5 × 3 + [0.5 × (−0.5) / 2] × 2 = 1 + 1.5 − 0.25 = 2.25.
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