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The polar section modulus of a solid circular shaft of diameter ‘d’ about an axis through its center of gravity is
- A(π /8) / d3
- B(π /16) / d3
- C(π /32) / d3
- D(π /64) / d3
Answer not set
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0
CCommunity
Polar section modulus <$(\begin{array}{l}
{{\rm{I}}_p} = \frac{\pi }{{32}}{d^4}\\
{Z_p} = \frac{{{I_p}}}{r} = \frac{{\frac{\pi }{{32}}{d^4}}}{{\frac{d}{2}}} = \frac{\pi }{{16}}{d^3}
\end{array})$
{{\rm{I}}_p} = \frac{\pi }{{32}}{d^4}\\
{Z_p} = \frac{{{I_p}}}{r} = \frac{{\frac{\pi }{{32}}{d^4}}}{{\frac{d}{2}}} = \frac{\pi }{{16}}{d^3}
\end{array})$
0
CCommunity
option number 3
0
CCommunity
option second is correct