The sum 1·2 + 2·3 + 3·4 + … + 10·11 is equal toA330B440C385D484 Correct answer: B ExplanationThe sum of n(n + 1) for n = 1 to 10 equals n(n + 1)(n + 2)/3 = 10 × 11 × 12 / 3 = 440. Join the discussion Report an error