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Using Euclid's algorithm, the gcd of 1071 and 462 is

2307Medium DSSSB TGT Computer Science 0 replies 1 views
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Using Euclid's algorithm, the gcd of 1071 and 462 is

  • A7
  • B33
  • C21
  • D42
Correct answer: C

Explanation

1071 = 2 × 462 + 147, 462 = 3 × 147 + 21 and 147 = 7 × 21, so the gcd is 21.

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