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Rs. 3,000 is divided among A, B and C, so that A receives 1/3 as much as B and C together receive and B receives 2/3 as much as A and C together receive. Then share of C is
- ARs. 525
- BRs. 1,625
- CRs. 1,050
- DRs. 600
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0
CCommunity
Given, 3,000 is divided among A, B and C, so that A receives 1/3 as much as B and C together receive and B receives 2/3 as much as A and C together receive
$(\Rightarrow {\rm{A}} = \frac{1}{3}{\rm{\;}}\left( {{\rm{\;B}} + {\rm{C}}} \right))$
⇒ 3A = B + C……….(1)
$(\Rightarrow {\rm{B}} = \frac{2}{3}{\rm{\;}}\left( {{\rm{\;A}} + {\rm{C}}} \right))$
⇒ 3B = 2A + 2C…………(2)
⇒ Putting the value of C from (1) into (2), we get,
⇒ 3B = 2 A + 2 (3A – B)
⇒ 8A = 5B …………….(3)
⇒ Similarly, we can solve and will get relation between B and C.
⇒ 7B = 8C …………….. (4)
⇒ Multiplying (3) with 7 and (4) with 5, we get,
⇒ 56A = 35B = 40C
$(\Rightarrow \frac{{56{\rm{A}}}}{{280}} = \frac{{35{\rm{B}}}}{{280}} = \frac{{40{\rm{C}}}}{{280}})$
$(\Rightarrow \frac{{\rm{A}}}{5} = \frac{{\rm{B}}}{8} = \frac{{\rm{C}}}{7})$
⇒ A : B : C = 5 : 8: 7
$(\Rightarrow {\rm{Share\;of\;C}} = \frac{7}{{20}} \times 3000 = 1050)$
$(\Rightarrow {\rm{A}} = \frac{1}{3}{\rm{\;}}\left( {{\rm{\;B}} + {\rm{C}}} \right))$
⇒ 3A = B + C……….(1)
$(\Rightarrow {\rm{B}} = \frac{2}{3}{\rm{\;}}\left( {{\rm{\;A}} + {\rm{C}}} \right))$
⇒ 3B = 2A + 2C…………(2)
⇒ Putting the value of C from (1) into (2), we get,
⇒ 3B = 2 A + 2 (3A – B)
⇒ 8A = 5B …………….(3)
⇒ Similarly, we can solve and will get relation between B and C.
⇒ 7B = 8C …………….. (4)
⇒ Multiplying (3) with 7 and (4) with 5, we get,
⇒ 56A = 35B = 40C
$(\Rightarrow \frac{{56{\rm{A}}}}{{280}} = \frac{{35{\rm{B}}}}{{280}} = \frac{{40{\rm{C}}}}{{280}})$
$(\Rightarrow \frac{{\rm{A}}}{5} = \frac{{\rm{B}}}{8} = \frac{{\rm{C}}}{7})$
⇒ A : B : C = 5 : 8: 7
$(\Rightarrow {\rm{Share\;of\;C}} = \frac{7}{{20}} \times 3000 = 1050)$
0
CCommunity
Given, 3,000 is divided among A, B and C, so that A receives 1/3 as much as B and C together receive and B receives 2/3 as much as A and C together receive
$(\Rightarrow {\rm{A}} = \frac{1}{3}{\rm{\;}}\left( {{\rm{\;B}} + {\rm{C}}} \right))$
⇒ 3A = B + C……….(1)
$(\Rightarrow {\rm{B}} = \frac{2}{3}{\rm{\;}}\left( {{\rm{\;A}} + {\rm{C}}} \right))$
⇒ 3B = 2A + 2C…………(2)
⇒ Putting the value of C from (1) into (2), we get,
⇒ 3B = 2 A + 2 (3A – B)
⇒ 8A = 5B …………….(3)
⇒ Similarly, we can solve and will get relation between B and C.
⇒ 7B = 8C …………….. (4)
⇒ Multiplying (3) with 7 and (4) with 5, we get,
⇒ 56A = 35B = 40C
$(\Rightarrow \frac{{56{\rm{A}}}}{{280}} = \frac{{35{\rm{B}}}}{{280}} = \frac{{40{\rm{C}}}}{{280}})$
$(\Rightarrow \frac{{\rm{A}}}{5} = \frac{{\rm{B}}}{8} = \frac{{\rm{C}}}{7})$
⇒ A : B : C = 5 : 8: 7
$(\Rightarrow {\rm{Share\;of\;C}} = \frac{7}{{20}} \times 3000 = 1050)$
$(\Rightarrow {\rm{A}} = \frac{1}{3}{\rm{\;}}\left( {{\rm{\;B}} + {\rm{C}}} \right))$
⇒ 3A = B + C……….(1)
$(\Rightarrow {\rm{B}} = \frac{2}{3}{\rm{\;}}\left( {{\rm{\;A}} + {\rm{C}}} \right))$
⇒ 3B = 2A + 2C…………(2)
⇒ Putting the value of C from (1) into (2), we get,
⇒ 3B = 2 A + 2 (3A – B)
⇒ 8A = 5B …………….(3)
⇒ Similarly, we can solve and will get relation between B and C.
⇒ 7B = 8C …………….. (4)
⇒ Multiplying (3) with 7 and (4) with 5, we get,
⇒ 56A = 35B = 40C
$(\Rightarrow \frac{{56{\rm{A}}}}{{280}} = \frac{{35{\rm{B}}}}{{280}} = \frac{{40{\rm{C}}}}{{280}})$
$(\Rightarrow \frac{{\rm{A}}}{5} = \frac{{\rm{B}}}{8} = \frac{{\rm{C}}}{7})$
⇒ A : B : C = 5 : 8: 7
$(\Rightarrow {\rm{Share\;of\;C}} = \frac{7}{{20}} \times 3000 = 1050)$