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The difference of pressure between the inside and outside of a liquid drop is

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The difference of pressure between the inside and outside of a liquid drop is
  • A(a)p = Txr
  • B(b)p = T/r
  • Cp = T/2r
  • D(d)p = 2T/r
Correct answer: D
0
CCommunity
(d)p = 2T/r
0
CCommunity
Pi×A=T×L+Po×A

(Pi-Po)×A=T×L

(Pi-Po)×πR^2=T×2πR

(Pi-Po)=2T/R