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A free standing brick wall 20 cm thick is subjected to a wind pressure of 75 kg/m². The maximum height of wall from stability consideration is
- A0.64 m
- B0.96 m
- C1.28 m
- D1.5 m
Correct answer: A
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0
CCommunity
0.64 m
0
CCommunity
(W*(0.19)2)/(1.5*p)=H
H=height of wall
P=wind load
W =unit weight 2000kg/m3( assume)
Here T=thickness 20 given but actual or effective thickness consider c/c=19cm
H=(2000(0.19)^2)/(1.5X75) =0.64m
H=height of wall
P=wind load
W =unit weight 2000kg/m3( assume)
Here T=thickness 20 given but actual or effective thickness consider c/c=19cm
H=(2000(0.19)^2)/(1.5X75) =0.64m