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The perimeter of a field in the shape of a rhombus is 116 m and one of its diagonals is 42 m. Its area is equal to the area of a rectangula…

3018Hard DSSSB TGT Computer Science 0 replies 2 views
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The perimeter of a field in the shape of a rhombus is 116 m and one of its diagonals is 42 m. Its area is equal to the area of a rectangular garden whose sides are in the ratio of 30 : 7. The perimeter of the rectangular garden is:

  • A185 m
  • B111 m
  • C222 m
  • D148 m
Correct answer: D

Explanation

Side of rhombus = 29 m. The other half-diagonal = √(29² − 21²) = 20, so the other diagonal is 40 m and the area is ½ × 42 × 40 = 840 m². For sides 30k and 7k, 210k² = 840 gives k = 2, so the sides are 60 m and 14 m and the perimeter is 148 m.

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