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S, T and U can complete a work in 40, 48 and 60 days respectively. They received Rs 10800 to complete the work. They begin the work togethe…

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S, T and U can complete a work in 40, 48 and 60 days respectively. They received Rs 10800 to complete the work. They begin the work together but T left 2 days before the completion of the work and U left 5 days before the completion of the work. S has completed the remaining work alone. What is the share of S (in Rs) from total money?
  • A4000
  • B4320
  • C4500
  • D4860
Answer not set
0
CCommunity
4860 is the correct answer as per the ssc answer key
0
CCommunity
s=40, t=48 , u=60

take lcm of 40 48 and 60, by doing so you will get a value which will be assumed as the total work.

lcm of 40,48,60=240.therefore total work is 240 units.

one day work of s=240/40=6

...........................t=240/48=5

...........................u=240/60=4

now let them complete the total work in x days so

6x+5(x-2)+4(x-5)=240

solving the above eqn we get the value of x as 18

therefore total work will be completed in 18 days

amount of work done by s=6*18=108

.........................................t=5*16=80

.........................................u=4*13=52

therefore payment received by s=10800/240*108=4860