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Solve for value of x and y if 5x - y = 5 and 3x + 2y = 29
- Ax = -3, y = 24
- Bx = 3, y = 10
- Cx = 12, y = 3
- Dx = 1, y = 4
Correct answer: B
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0
CCommunity
x = 3, y = 10
x = 3, y = 10
x = 3, y = 10
0
CCommunity
Solution:
Given equations:
5x - y = 5 --------->1 and
3x + 2y = 29 ---------->2
Multiply eqn1 by 2 we get
10x - 2y = 10 ---------->3
Adding eqn3 and eqn2, we get
10x - 2y + 3x + 2y = 10 + 29
13x = 39
y = 39/13
y = 3
Substituting the value of y in eqn we get,
1 => 5x - (3) = 5
5x = 5 + 3
5x = 8
x = 8/5
x = 1.6
So, x = 1.6 and y = 3
Given equations:
5x - y = 5 --------->1 and
3x + 2y = 29 ---------->2
Multiply eqn1 by 2 we get
10x - 2y = 10 ---------->3
Adding eqn3 and eqn2, we get
10x - 2y + 3x + 2y = 10 + 29
13x = 39
y = 39/13
y = 3
Substituting the value of y in eqn we get,
1 => 5x - (3) = 5
5x = 5 + 3
5x = 8
x = 8/5
x = 1.6
So, x = 1.6 and y = 3
0
CCommunity
x = 3
y = 10
y = 10