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Due to increase of 33.33% in the price of apples, a customer can purchase 4 apples less for Rs 16. What is the original price (in paise) of an apple?
- A100
- B125
- C150
- D$\frac{400}{3}$
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0
CCommunity
Option option 1 is the correct answer
0
CCommunity
Let the original price of an apple = 3x paise
1 Rs. = 100 paise
16 Rs. = 1600 paise
= Number of apples he can purchase with this price $= \frac{1600}{3x}$
New price of apple after 33.33% increase $= 3x+\frac{1}{3}\times3x=4x$ paise
= Number of applies he can purchase with the increased price $=\frac{1600}{4x} $
Due to the increase in the price, 4 less apples can be purchased.
= $\frac{1600}{3x}-\frac{1600}{4x}=4$
= $\frac{1600}{x}(\frac{1}{3}-\frac{1}{4})=4$
= $400(\frac{4-3}{12})=x$
= $x=\frac{400}{12}=\frac{100}{3}$
$\therefore$ Original price (in paise) of an apple $=3\times\frac{100}{3}=100$ paise
= Ans - (A)
1 Rs. = 100 paise
16 Rs. = 1600 paise
= Number of apples he can purchase with this price $= \frac{1600}{3x}$
New price of apple after 33.33% increase $= 3x+\frac{1}{3}\times3x=4x$ paise
= Number of applies he can purchase with the increased price $=\frac{1600}{4x} $
Due to the increase in the price, 4 less apples can be purchased.
= $\frac{1600}{3x}-\frac{1600}{4x}=4$
= $\frac{1600}{x}(\frac{1}{3}-\frac{1}{4})=4$
= $400(\frac{4-3}{12})=x$
= $x=\frac{400}{12}=\frac{100}{3}$
$\therefore$ Original price (in paise) of an apple $=3\times\frac{100}{3}=100$ paise
= Ans - (A)