In an examination 38% of students fail in English and 61% pass in Hindi and 23% fail in both. Find the actual failure percentage?

54%

NA

Solution :

Let 'A' represent the event of failure in English and

Let 'B' represent the event of failure in Hindi.

Given: n (A) = 38%

Number of students passed in Hindi = 61% . So,

Number of students failed in Hindi = 100% - 61% = 39%

Number of students failed in both = 23%

We know that,

n ( A union B) = n (A) + n (B) - n (A intersection B)

n ( A union B) = 38% + 39% - 23%

n ( A union B) = 77% - 23%

n ( A union B) = 54%

So, the correct option is C). 54%