CCommunity
Solution:
Let the third number be 'x'.
Given: First number is 20% more than x,
So, First number = (20/100)x + x = 0.2x + x = 1.2x
Second number is 25% more than x,
So, Second number= (25/100)x + x = 0.25x +x = 1.25x
Let the first number be y% of second number,so,
y = (1.2x/1.25x)×100
y = 0.96 × 100
y = 96%
So, the correct option is C). 96%