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The specific gravity of an oil whose specific weight is 7.85 kN/m3, is
- A0.8
- B1
- C1.2
- D1.6
Correct answer: A
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0
CCommunity
0.8
0
CCommunity
Solution:
Specific gravity of the oil
= Specific weight of the oil / Specific weight of water
We know that, Specific weight of water = 9.81 kN/m³
So, => (7.85 / 9.81)(kNm³/kNm³)
= 0.8
So, the correct option is A). 0.8
Specific gravity of the oil
= Specific weight of the oil / Specific weight of water
We know that, Specific weight of water = 9.81 kN/m³
So, => (7.85 / 9.81)(kNm³/kNm³)
= 0.8
So, the correct option is A). 0.8