54
What number should be added to each of the numbers 35, 115, 53 and 165, so that the resulting numbers are in continued proportion?
- A10
- B12
- C8
- D6
Answer not set
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0
CCommunity
10 is the correct answer as per the ssc answer key
0
CCommunity
Let the no. be x
(35+x):(115+x)=(53+x):(165+x)
=(35+x)*(165+x)=(53+x)*(115+x)
=5775+200x+x^2=6095+168x+x^2
=200x-168x=6095-5775
=32x=320
x= 10
(35+x):(115+x)=(53+x):(165+x)
=(35+x)*(165+x)=(53+x)*(115+x)
=5775+200x+x^2=6095+168x+x^2
=200x-168x=6095-5775
=32x=320
x= 10