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Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers.
(i) 26 and 91
(ii) 510 and 92
(iii) 336 and 54
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0
CCommunity
1. $26$ and $91$
Factors of above numbers are:
$26 = 2 \times 13$
$91 = 7 \times 13$
Common factors are: 13
Hence HCF is: $13$
LCM is: $13 \times 2 \times 7 = 182$
Factors of above numbers are:
$26 = 2 \times 13$
$91 = 7 \times 13$
Common factors are: 13
Hence HCF is: $13$
LCM is: $13 \times 2 \times 7 = 182$
0
CCommunity
2. $510$ and $92$
$92 = 2×2×23$
$510 = 2×3×5×17$
Common Factors are: $2$
Hence HCF is $2$
LCM = $2^2 \times 3 \times 5 \times 17 \times 23 = 23460$
$92 = 2×2×23$
$510 = 2×3×5×17$
Common Factors are: $2$
Hence HCF is $2$
LCM = $2^2 \times 3 \times 5 \times 17 \times 23 = 23460$
0
CCommunity
3. $336$ and $54%
$336 = 2 × 2 × 2 × 2 × 3 × 7$
$54 = 2 × 3 × 3 × 3$
Highest Common Factor: $2 \times 3$
Hence HCF = $6$
LCM Would be $= 2^4 \times 3 \times 7 \times 2 \times 3 \times 3 \times 3 = 3024$
$336 = 2 × 2 × 2 × 2 × 3 × 7$
$54 = 2 × 3 × 3 × 3$
Highest Common Factor: $2 \times 3$
Hence HCF = $6$
LCM Would be $= 2^4 \times 3 \times 7 \times 2 \times 3 \times 3 \times 3 = 3024$