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Suppose that a biased coin is tossed such that P(H) = 2/3 and P(T) = 1/3. If head (H) appears, a number between is selected between 1 throu…

358888Medium DSSSB TGT Computer Science 0 replies 0 views
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Suppose that a biased coin is tossed such that P(H) = 2/3 and P(T) = 1/3. If head (H) appears, a number between is selected between 1 through 9. If tail (T) appears, then a number is selected between 1 through 5. The probability that an even number is selected is approximately equal to:
  • A0.92
  • B0.87
  • C0.56
  • D0.43
Correct answer: D

Explanation

P(even) = 2/3 × (4/9) + 1/3 × (2/5) = 8/27 + 2/15 = 0.296 + 0.133 = 0.43 (approximately).

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