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A can do a certain work in 14 days. B is 331⁄3% less efficient than A. Both started to work together, but A left the work 2 days before the…

3622Medium DSSSB TGT Computer Science 0 replies 2 views

A can do a certain work in 14 days. B is 33¹⁄₃% less efficient than A. Both started to work together, but A left the work 2 days before the completion of the work and B continued to work till the work was over. In how many days was the whole work completed?

A9³⁄₅
B8¹⁄₄
C8¹⁄₂
D10²⁄₅

Correct answer: A

Explanation

B’s efficiency is 2/3 of A’s, so B alone takes 21 days. If the work lasts T days, B works T days and A works (T − 2) days: (T − 2)/14 + T/21 = 1. So 3(T − 2) + 2T = 42, 5T = 48 and T = 9 3/5 days.

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