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A can do a work in 9 days, if B is 50 % more efficient than A, then in how many days can B do the same work ?

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A can do a work in 9 days, if B is 50 % more efficient than A, then in how many days can B do the same work ?
  • A13.5 days
  • B4.5 days
  • C6 days
  • D3 days
Answer not set
0
CCommunity
Hello, 6 days is correct
0
CCommunity
Let total work to be done=1

Then, A's one day work= (total work) / (total days taken by A)

(=1/9)B's one day work= 150% of A's one day work (because B is 50% more efficient)

=(1/9)*(150/100)

=1/6 Total time taken by B to do total work = 6 days