0Given the following table of values of f(x) = log x, what is the value of f′(3)?x1234f(x)00.3010.4770.602A0.208B0.278C0.125D0.225 Correct answer: C ExplanationForward difference: f′(3) ≈ [f(4) − f(3)]/h = (0.602 − 0.477)/1 = 0.125. Join the discussion Report an error Share