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A discrete random variable X has the following probability distribution. What is the value of K?X1234567P(X)K2K2K3KK22K27K2 + K

5256Medium DSSSB TGT Computer Science 0 replies 0 views
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A discrete random variable X has the following probability distribution. What is the value of K?
X1234567
P(X)K2K2K3KK22K27K2 + K
  • A1/30
  • B1/10
  • C1/20
  • D1/40
Correct answer: B

Explanation

ΣP(X) = 1: K + 2K + 2K + 3K + K² + 2K² + 7K² + K = 10K² + 9K = 1, so 10K² + 9K − 1 = 0, giving K = 1/10 (K = −1 is rejected as probability cannot be negative).

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