49
The least number which when divided by 16, 18. 20 and 25 leaves 4 as remainder in each case but when divided by 7 leaves no remainder is
- A17004
- B18000
- C18002
- D18004
Answer not set
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0
CCommunity
option 4 is the answer
0
CCommunity
LCM of 16, 18, 20 and 25
= 3600
Required number = 3600K +
4 which is exactly divisible by 7
for certain value of K.
When K = 5,
number = 3600 × 5 + 4
= 18004 which is exactly divisible
by 7
= 3600
Required number = 3600K +
4 which is exactly divisible by 7
for certain value of K.
When K = 5,
number = 3600 × 5 + 4
= 18004 which is exactly divisible
by 7