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What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7
- A37
- B36
- C39
- D30
Answer not set
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0
CCommunity
39
0
CCommunity
LCM of 9, 10 and 15 = 90
Þ The multiple of 90 are also divisible
by 9, 10 or 15.
\ 21 × 90 = 1890 will be divisible
by them.
\ Now, 1897 will be the number
that will give remainder 7.
1936 – 1897
Required number
= 1936 – 1897 = 39
Þ The multiple of 90 are also divisible
by 9, 10 or 15.
\ 21 × 90 = 1890 will be divisible
by them.
\ Now, 1897 will be the number
that will give remainder 7.
1936 – 1897
Required number
= 1936 – 1897 = 39