23
Find the least number which when divided separately by 15, 20. 36 and 48 leaves 3 as remainder in each case.
- A183
- B243
- C483
- D723
Answer not set
Log in or create a free account to reply and vote.
0
CCommunity
option 4 : 723 is correct
0
CCommunity
Required number = (LCM of 15, 20, 36 and 48) + 3
LCM = 2 × 2 × 3 × 5 × 3 × 4 = 720
Required number = 720 + 3 = 723
LCM = 2 × 2 × 3 × 5 × 3 × 4 = 720
Required number = 720 + 3 = 723