A milk vendor has 21 litres of cow milk. 42 litres of toned milk and 63 litres of double toned milk. If he wants to pack them in cans so th… — Answer & Discussion

A milk vendor has 21 litres of cow milk. 42 litres of toned milk and 63 litres of double toned milk. If he wants to pack them in cans so that each can contains same litres of milk and does not want to mix any two kinds of milk in a can, then the least number of cans required Is

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CCommunity20 Jan 2018

I think option 2 is the right answer

CCommunity09 Apr 2018

Maximum quantity in each can= HCF of 21, 42 and 63 litres= 21 litres

Required least number of cans

= $\frac{21}{21}+\frac{42}{21}+\frac{63}{21}$

= 1+2+3 = 6

CCommunity23 Nov 2018

Hcf of 3 no. is 21

Divide 21 by each and add those results

1+2+3=6