Two numbers, both greater than 29, have HCF 29 and LCM 4147. The sum of the numbers is :

I think option 2 is the right answer

Let the number be 29x and 29y respectively where x and y are prime to each other.

LCM of 29x and 29y = 29xy

Now, 29xy = 4147 xy =$\frac{4147}{29}$ = 143

Thus xy = 11 × 13

Numbers are 29 × 11 = 319 and 29 × 13 = 377

Required sum = 377 + 319 = 696