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The sum of two numbers is 216 and their HCF is 27. How many pairs of such numbers are there
- A1
- B2
- C3
- D0
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CCommunity
option 2 : - 2
0
CCommunity
HCF of two numbers = 27
Let the numbers be 27x and 27y where x and y are prime to each other.
According to the question, 27x + 27y = 216 27 (x + y) = 216 x + y =$\frac{216}{27}$=8
Possible pairs of x and y = (1, 7) and (3, 5)
Numbers =(27, 189) and (81, 135)
Let the numbers be 27x and 27y where x and y are prime to each other.
According to the question, 27x + 27y = 216 27 (x + y) = 216 x + y =$\frac{216}{27}$=8
Possible pairs of x and y = (1, 7) and (3, 5)
Numbers =(27, 189) and (81, 135)