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Sum of two numbers is 384. H.C.F. of the numbers is 48. The difference of the numbers is
- A100
- B192
- C288
- D336
Answer not set
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CCommunity
3). 288
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CCommunity
Let the numbers be 48x and 48y where x and y are co-primes.
48x + 48y = 384 Þ 48 ( x + y) = 384 Þ x + y = 384 / 48 = 8 ........... (i)
Possible and acceptable pairs of x and y satisfying this condition are : (1, 7) and (3, 5).
Numbers are : 48 × 1 = 48 and 48 × 7 = 336 and 48 × 3 = 144 and 48 × 5 = 240
Required difference = 336 – 48 = 288
48x + 48y = 384 Þ 48 ( x + y) = 384 Þ x + y = 384 / 48 = 8 ........... (i)
Possible and acceptable pairs of x and y satisfying this condition are : (1, 7) and (3, 5).
Numbers are : 48 × 1 = 48 and 48 × 7 = 336 and 48 × 3 = 144 and 48 × 5 = 240
Required difference = 336 – 48 = 288