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The sum of two numbers is 36 and their H.C.F. is 4. How many pairs of such numbers are possible
- A1
- B2
- C3
- D4
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0
CCommunity
Correct answer is: option 3
0
CCommunity
HCF of two numbers = 4.
Hence, the numbers can be given by 4x and 4y where x and y are co-prime.
Then, 4x + 4y = 36
4 (x + y) = 36
x + y = 9
Possible pairs satisfying this condition are : (1, 8), (4, 5), (2, 7)
Hence, the numbers can be given by 4x and 4y where x and y are co-prime.
Then, 4x + 4y = 36
4 (x + y) = 36
x + y = 9
Possible pairs satisfying this condition are : (1, 8), (4, 5), (2, 7)