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The LCM of two positive integers is twice the larger number. The difference of the smaller number and the GCD of the two numbers is 4.The smaller number is :
- A12
- B6
- C8
- D10
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0
CCommunity
option 3 is the correct answer as per the answer key
0
CCommunity
Let the numbers be x H and
yH where H is the HCF and yH
> x H.
LCM = xy H
xyH = 2yH Þ x = 2
Again, x H – H = 4
2H – H = 4 Þ H = 4
Smaller number = x H = 8
yH where H is the HCF and yH
> x H.
LCM = xy H
xyH = 2yH Þ x = 2
Again, x H – H = 4
2H – H = 4 Þ H = 4
Smaller number = x H = 8