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A number between 1000 and 2000 which when divided by 30,' 36 and 80 gives a remainder 11 in each case is
- A1451
- B1641
- C1712
- D1523
Answer not set
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0
CCommunity
option 1 : 1451 is correct
0
CCommunity
LCM = 2 × 2 × 3 × 3 × 4 × 5
= 720
Required number
= 2 × 720 + 11
= 1440 + 11 = 1451
= 720
Required number
= 2 × 720 + 11
= 1440 + 11 = 1451
0
CCommunity
LCM of 30, 36 and 80 =720, 1000 divided by 720 =remaider 280, =1000+(720-280)=1440, required number=1440+11=1451