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The greatest number, that divides 122 and 243 leaving respectively 2 and 3 as remainders, is

5486Medium 2 replies 2,408 views
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CCommunity
Option option 4 is the correct answer
0
CCommunity
Clearly, $122 – 2 = 120$ and $243 – 3 = 240$ are exactly divisible by the required number.

Required number $=$ HCF of $120, 240 = 120$