26
$(32)^{3} + (79)^{3} -(111 )^{3} + 3\times 32\times 79\times 111$ is equal to
- A10000
- B0
- C30007
- D1
Answer not set
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0
CCommunity
0 : - is correct hence option 2
0
CCommunity
Using (x) of Basic Formulae
Let, 32 = a
79 = b, –111 = c
When (a + b + c) = 0
then a3 + b3 + c3 - 3abc = 0
Here, a+ b+c = 32+79–111 = 0
$\therefore$ (32)3+ (79)3 – (111)3 + 3 × 32× 79 × 111 = 0.
Let, 32 = a
79 = b, –111 = c
When (a + b + c) = 0
then a3 + b3 + c3 - 3abc = 0
Here, a+ b+c = 32+79–111 = 0
$\therefore$ (32)3+ (79)3 – (111)3 + 3 × 32× 79 × 111 = 0.