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If $1^{3}+2^{3} + ... +10^{3}$ = 3025, then 4 + 32 + 108......4000 is equal to :
- A12000
- B12100
- C12200
- D12400
Answer not set
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0
CCommunity
I think option 2 is the right answer
0
CCommunity
Now, 4 + 32 + 108 + .... + 4000
= 4 (1 + 8 + 27 + .... + 4000)
= 4 × 3025 = 12100
= 4 (1 + 8 + 27 + .... + 4000)
= 4 × 3025 = 12100