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2sinAsinB is equal to
- Asin(A+B) + sin(A - B)
- Bcos(A - B) - cos(A+B)
- Csin(A+B) - sin(A - B)
- Dcos(A+B) + cos(A - B)
Answer not set
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0
CCommunity
right answer for this question is option 2
0
CCommunity
cos(A - B) - cos(A+B)
0
CCommunity
2sinasinb$ = cos(A - B) - cos(A+B)
0
CCommunity
2 sinAcosB = sin(A + B) + sin(A − B)
2 cosAcosB = cos(A − B) + cos(A + B)
2 sinAsinB = cos(A − B) − cos(A + B)
2 cosAcosB = cos(A − B) + cos(A + B)
2 sinAsinB = cos(A − B) − cos(A + B)