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The average of 29 consecutive even integers is 60. The highest of these integers is
- A88
- B118
- C176
- D120
Answer not set
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CCommunity
88
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CCommunity
first even no be n
next one will be n+2 and then n+4 and so on.. till n+56
average of numbers = n+n+2+n+4+......+ n+56/ 29
(29n + 2+4+....+56) / 29 =60
2+4+..+56 = 28/2[2*2 + (28-1)2] (sum of AP with d=2)
=14*58=812
29n+ 812=29*60=1740
29n=928
n=32
highest value =n+56=32+56=88
next one will be n+2 and then n+4 and so on.. till n+56
average of numbers = n+n+2+n+4+......+ n+56/ 29
(29n + 2+4+....+56) / 29 =60
2+4+..+56 = 28/2[2*2 + (28-1)2] (sum of AP with d=2)
=14*58=812
29n+ 812=29*60=1740
29n=928
n=32
highest value =n+56=32+56=88