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A trader had 16 quintals of wheat. He sold a part of it at 17% profit and the rest at 27% profit, so that he made a total profit of 21%. Ho…

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A trader had 16 quintals of wheat. He sold a part of it at 17% profit and the rest at 27% profit, so that he made a total profit of 21%. How much wheat
did he sell at 27% profit
  • A960 kg
  • B640 kg
  • C320 kg
  • D1280 kg
Answer not set
0
CCommunity
option 2 is the correct answer as per the answer key
0
CCommunity
From the question we can say,

Total amount of wheat = 16 Quintals

Let us take the first amount of wheat which earned 17% profit for the trader as 'x'.

So the second amount of wheat which earned 27% profit would be '(16-x)'.

Profit earned by selling 'x' amount of wheat =17x/100

Profit earned by selling '(16-x)' amount of wheat =(16-x)27/100

Therefore by equating we get,

Total Profit = Profit earned for the First part + Second part

16×21/100 =17x/100+ (16-x)27/100

336/100=17x/100+16×27/100 -27x/100

336/100 = 17x/100 +432/100 - 27x/100

336 = 17x + 432 -27x

336 = -10x + 432

10x = 432 - 336

10x = 96

x = 96/10

x = 9.6

Amount of wheat sold at 27% = (16 - x)

= 16 - 9.6 = 6.4 Quintals

( 1 Quintal = 100 kg )

So, 6.4 Quintals is 640 kg

The correct answer is 2). 640 kg