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The compound interest accrued in 2 years on a principal of Rs. 15,800 is Rs.7716.72. What is the rate of interest p.c.p.a. ?
- A22
- B16
- C18
- D20
Answer not set
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0
CCommunity
Solution
Amount = 15800 + 7716.72 = Rs. 23,516.72
$A = P (1 + \frac{R}{100})^T$
=> $23,516.72 = 15,800 (1 + \frac{R}{100})^2$
=> $\frac{23,516.72}{15,800} = (1 + \frac{R}{100})^2$
=> $\frac{14884}{10000} = (1 + \frac{R}{100})^2$
=> $(1 + \frac{R}{100})^2 = (\frac{122}{100})^2$
=> $1 + \frac{R}{100} = \frac{122}{100}$
=> $\frac{R}{100} = \frac{122}{100} - 1$
=> $\frac{R}{100} = \frac{22}{100}$
=> $R = 22 \%$
Amount = 15800 + 7716.72 = Rs. 23,516.72
$A = P (1 + \frac{R}{100})^T$
=> $23,516.72 = 15,800 (1 + \frac{R}{100})^2$
=> $\frac{23,516.72}{15,800} = (1 + \frac{R}{100})^2$
=> $\frac{14884}{10000} = (1 + \frac{R}{100})^2$
=> $(1 + \frac{R}{100})^2 = (\frac{122}{100})^2$
=> $1 + \frac{R}{100} = \frac{122}{100}$
=> $\frac{R}{100} = \frac{122}{100} - 1$
=> $\frac{R}{100} = \frac{22}{100}$
=> $R = 22 \%$
0
CCommunity
Solution
Amount = 15800 + 7716.72 = Rs. 23,516.72
$A = P (1 + \frac{R}{100})^T$
=> $23,516.72 = 15,800 (1 + \frac{R}{100})^2$
=> $\frac{23,516.72}{15,800} = (1 + \frac{R}{100})^2$
=> $\frac{14884}{10000} = (1 + \frac{R}{100})^2$
=> $(1 + \frac{R}{100})^2 = (\frac{122}{100})^2$
=> $1 + \frac{R}{100} = \frac{122}{100}$
=> $\frac{R}{100} = \frac{122}{100} - 1$
=> $\frac{R}{100} = \frac{22}{100}$
=> $R = 22 \%$
Amount = 15800 + 7716.72 = Rs. 23,516.72
$A = P (1 + \frac{R}{100})^T$
=> $23,516.72 = 15,800 (1 + \frac{R}{100})^2$
=> $\frac{23,516.72}{15,800} = (1 + \frac{R}{100})^2$
=> $\frac{14884}{10000} = (1 + \frac{R}{100})^2$
=> $(1 + \frac{R}{100})^2 = (\frac{122}{100})^2$
=> $1 + \frac{R}{100} = \frac{122}{100}$
=> $\frac{R}{100} = \frac{122}{100} - 1$
=> $\frac{R}{100} = \frac{22}{100}$
=> $R = 22 \%$