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Two chairs and three tables cost Rs 1025/- and 3 chairs and 2 tables cost is Rs 1,100/- .What is the difference between the cost one table and chair?
- A75
- B35
- C125
- DCannot be determined
Answer not set
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0
CCommunity
Solution
Let cost price of 1 chair = $Rs.$ $x$ and cost price of 1 table = $Rs.$ $y$
=> $2x+3y=1025$ -----------(i)
and $3x+2y=1100$ --------(ii)
Subtracting equation (i) from (ii)
=> $(3x-2x)+(2y-3y)=(1100-1025)$
=> $x-y=75$
$\therefore$ Difference between the cost one table and chair = Rs. 75
=> Ans - (A)
Let cost price of 1 chair = $Rs.$ $x$ and cost price of 1 table = $Rs.$ $y$
=> $2x+3y=1025$ -----------(i)
and $3x+2y=1100$ --------(ii)
Subtracting equation (i) from (ii)
=> $(3x-2x)+(2y-3y)=(1100-1025)$
=> $x-y=75$
$\therefore$ Difference between the cost one table and chair = Rs. 75
=> Ans - (A)
0
CCommunity
Solution
Let cost price of 1 chair = $Rs.$ $x$ and cost price of 1 table = $Rs.$ $y$
=> $2x+3y=1025$ -----------(i)
and $3x+2y=1100$ --------(ii)
Subtracting equation (i) from (ii)
=> $(3x-2x)+(2y-3y)=(1100-1025)$
=> $x-y=75$
$\therefore$ Difference between the cost one table and chair = Rs. 75
=> Ans - (A)
Let cost price of 1 chair = $Rs.$ $x$ and cost price of 1 table = $Rs.$ $y$
=> $2x+3y=1025$ -----------(i)
and $3x+2y=1100$ --------(ii)
Subtracting equation (i) from (ii)
=> $(3x-2x)+(2y-3y)=(1100-1025)$
=> $x-y=75$
$\therefore$ Difference between the cost one table and chair = Rs. 75
=> Ans - (A)