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The speed of a boat in still water is 500% more than the speed of the current. What is the respective ratio between the speed of the boat downstream and speed of the boat upstream ?
- A9 : 2
- B7 : 3
- C7 : 5
- D9 : 4
Answer not set
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0
CCommunity
Solution
Let speed of current = $x$ km/h
=> Speed of boat in still water = $x + (\frac{500}{100} \times x)$
= $x + 5x = 6x$ km/h
=> Speed of the boat downstream = $6x + x = 7x$ km/h
Speed of boat upstream = $6x - x = 5x$ km/h
$\therefore$ Required ratio = $\frac{7x}{5x}$
= $7 : 5$
Let speed of current = $x$ km/h
=> Speed of boat in still water = $x + (\frac{500}{100} \times x)$
= $x + 5x = 6x$ km/h
=> Speed of the boat downstream = $6x + x = 7x$ km/h
Speed of boat upstream = $6x - x = 5x$ km/h
$\therefore$ Required ratio = $\frac{7x}{5x}$
= $7 : 5$
0
CCommunity
Solution
Let speed of current = $x$ km/h
=> Speed of boat in still water = $x + (\frac{500}{100} \times x)$
= $x + 5x = 6x$ km/h
=> Speed of the boat downstream = $6x + x = 7x$ km/h
Speed of boat upstream = $6x - x = 5x$ km/h
$\therefore$ Required ratio = $\frac{7x}{5x}$
= $7 : 5$
Let speed of current = $x$ km/h
=> Speed of boat in still water = $x + (\frac{500}{100} \times x)$
= $x + 5x = 6x$ km/h
=> Speed of the boat downstream = $6x + x = 7x$ km/h
Speed of boat upstream = $6x - x = 5x$ km/h
$\therefore$ Required ratio = $\frac{7x}{5x}$
= $7 : 5$