23
405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total no. of children. How many sweets did each child receive ?
- A15
- B45
- C9
- D18
Answer not set
Log in or create a free account to reply and vote.
0
CCommunity
Solution
Let the number of children be C.
So, the number of sweets that each child gets is 20% of C.
Hence, the total number of sweets there are is 20%*C*C which equals 405.
So, $20 \%C^2 = 405$ or $C^2 = 2025$
Hence, C=45 and the number of sweets each child gets is 9
Let the number of children be C.
So, the number of sweets that each child gets is 20% of C.
Hence, the total number of sweets there are is 20%*C*C which equals 405.
So, $20 \%C^2 = 405$ or $C^2 = 2025$
Hence, C=45 and the number of sweets each child gets is 9
0
CCommunity
Solution
Let the number of children be C.
So, the number of sweets that each child gets is 20% of C.
Hence, the total number of sweets there are is 20%*C*C which equals 405.
So, $20 \%C^2 = 405$ or $C^2 = 2025$
Hence, C=45 and the number of sweets each child gets is 9
Let the number of children be C.
So, the number of sweets that each child gets is 20% of C.
Hence, the total number of sweets there are is 20%*C*C which equals 405.
So, $20 \%C^2 = 405$ or $C^2 = 2025$
Hence, C=45 and the number of sweets each child gets is 9
0
CCommunity
Let number of children be x
\therefore No. of sweets received by each 405 child =
405
x
=>
405
x
=20%ofx
=>
405
x
=
x
5
=>x2=405×5
=> x=
√
405×5
=
√
81×5×5
=9×5=45
∴ Required no. of sweets received by each child =
405
45
=9
\therefore No. of sweets received by each 405 child =
405
x
=>
405
x
=20%ofx
=>
405
x
=
x
5
=>x2=405×5
=> x=
√
405×5
=
√
81×5×5
=9×5=45
∴ Required no. of sweets received by each child =
405
45
=9