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Abhijit invested a certain sum at simple interest in a company X at the rate of 15% per annum. He invested the total amount received after…

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Abhijit invested a certain sum at simple interest in a company X at the rate of 15% per annum. He invested the total amount received after two years from company X in another company Y at compound interest for two years at the rate of 12% per annum compounded annually. He received Rs. 81536 at the end of two years. What sum did he invest in company X in the beginning ?
  • ARs. 65000
  • BRs. 60000
  • CRs.56000
  • DRs.50000
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CCommunity
Solution
Let amount invested in company X = Rs. $100x$
=> S.I. = $\frac{Principal \times Rate \times Time}{100}$
= $\frac{100x \times 15 \times 2}{100} = 30x$
$\therefore$ Amount invested in company Y = $100x + 30x$
= Rs. $130x$
$\therefore A = P (1 + \frac{R}{100})^T$
=> $81536 = 130x (1 + \frac{12}{100})^2$
=> $81536 = 130x \times \frac{28}{25} \times \frac{28}{25}$
=> $x = \frac{81536 \times 25 \times 25}{130 \times 28 \times 28}$
=> $x = 500$
$\therefore$ Amount invested in company X in the beginning = $100 \times 500$
= Rs. $50,000$
0
CCommunity
Solution
Let amount invested in company X = Rs. $100x$
=> S.I. = $\frac{Principal \times Rate \times Time}{100}$
= $\frac{100x \times 15 \times 2}{100} = 30x$
$\therefore$ Amount invested in company Y = $100x + 30x$
= Rs. $130x$
$\therefore A = P (1 + \frac{R}{100})^T$
=> $81536 = 130x (1 + \frac{12}{100})^2$
=> $81536 = 130x \times \frac{28}{25} \times \frac{28}{25}$
=> $x = \frac{81536 \times 25 \times 25}{130 \times 28 \times 28}$
=> $x = 500$
$\therefore$ Amount invested in company X in the beginning = $100 \times 500$
= Rs. $50,000$