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The average age of a man and his son is 48 years. The ratio of their ages is 11 : 5 respectively. What will be ratio of their ages after 6 years ?
- A6 : 5
- B5 : 3
- C4 : 3
- D2 : 1
Answer not set
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0
CCommunity
Solution
Let age of man = $11x$ and age of son = $5x$
Sum of ages of man and son = 48 * 2 = 96 years
=> $11x + 5x = 96$
=> $x = \frac{96}{16} = 6$
=> Age of man = 11 * 6 = 66 years
Age of son = 5 * 6 = 30 years
=> Age of man after 6 years = 66 + 6 = 72 years
Age of son after 6 years = 30 + 6 = 36 years
$\therefore$ Required ratio = 72 : 36 = 2 : 1
Let age of man = $11x$ and age of son = $5x$
Sum of ages of man and son = 48 * 2 = 96 years
=> $11x + 5x = 96$
=> $x = \frac{96}{16} = 6$
=> Age of man = 11 * 6 = 66 years
Age of son = 5 * 6 = 30 years
=> Age of man after 6 years = 66 + 6 = 72 years
Age of son after 6 years = 30 + 6 = 36 years
$\therefore$ Required ratio = 72 : 36 = 2 : 1
0
CCommunity
Solution
Let age of man = $11x$ and age of son = $5x$
Sum of ages of man and son = 48 * 2 = 96 years
=> $11x + 5x = 96$
=> $x = \frac{96}{16} = 6$
=> Age of man = 11 * 6 = 66 years
Age of son = 5 * 6 = 30 years
=> Age of man after 6 years = 66 + 6 = 72 years
Age of son after 6 years = 30 + 6 = 36 years
$\therefore$ Required ratio = 72 : 36 = 2 : 1
Let age of man = $11x$ and age of son = $5x$
Sum of ages of man and son = 48 * 2 = 96 years
=> $11x + 5x = 96$
=> $x = \frac{96}{16} = 6$
=> Age of man = 11 * 6 = 66 years
Age of son = 5 * 6 = 30 years
=> Age of man after 6 years = 66 + 6 = 72 years
Age of son after 6 years = 30 + 6 = 36 years
$\therefore$ Required ratio = 72 : 36 = 2 : 1