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In an examination it is required to get 310 of the aggregate marks to pass. A student gets 28% marks and is declared failed by 93 marks. What are the maximum aggregate marks a student can get ?
- A685
- B765
- C775
- DCannot be determined
Answer not set
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0
CCommunity
Solution
Let the max marks in the exam = $100x$
Passing marks = 310
Now, acc to ques,
=> $(\frac{28}{100} * 100x) + 93 = 310$
=> $28x = 310 - 93$
=> $x = \frac{217}{28} = 7.75$
$\therefore$ Max marks = 100 * 7.75 = 775
Let the max marks in the exam = $100x$
Passing marks = 310
Now, acc to ques,
=> $(\frac{28}{100} * 100x) + 93 = 310$
=> $28x = 310 - 93$
=> $x = \frac{217}{28} = 7.75$
$\therefore$ Max marks = 100 * 7.75 = 775
0
CCommunity
Solution
Let the max marks in the exam = $100x$
Passing marks = 310
Now, acc to ques,
=> $(\frac{28}{100} * 100x) + 93 = 310$
=> $28x = 310 - 93$
=> $x = \frac{217}{28} = 7.75$
$\therefore$ Max marks = 100 * 7.75 = 775
Let the max marks in the exam = $100x$
Passing marks = 310
Now, acc to ques,
=> $(\frac{28}{100} * 100x) + 93 = 310$
=> $28x = 310 - 93$
=> $x = \frac{217}{28} = 7.75$
$\therefore$ Max marks = 100 * 7.75 = 775