In AUTOMATIC we have 2 'A' and 2 'T', which implies from the code PUVBMBUDJ A & T can be 'U' / 'B' Case 1: If A is coded as B(which is 1+the position of A), then this gives us code BVUPNBUDJ. The BUDJ( half of the part of the code matches) which lead us to the rest half BUVP which is in reverse leaving the middle term 'M' unchanged Case 2: if A is coded as U : No need to perform that.
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CCommunity
Solution
The word AUTOMATIC is divided into three parts : AUTO , M , ATIC
I : AUTO - PUVB
The diagonally opposite element is substituted by its immediate following alphabet in the English alphabetical series.
=> A is substituted by B at its diagonally opposite position. Similarly, U is substituted by V at its diagonally opposite position and similarly T & O by U and P.
II : M - M
The middle letter is used as it is.
III : ATIC - BUJD
The opposite (not diagonally) element is substituted by its immediate following alphabet in the English alphabetical series.
=> A is substituted by B at its opposite position. Similarly T is substituted by U at its opposite position and similarly I & C by J and D.
Thus, code for BUILDINGS :
BUIL - MJVC
D - D
INGS - JOHT
$\therefore$ BUILDINGS - MJVCDJOHT
0
CCommunity
Solution
The word AUTOMATIC is divided into three parts : AUTO , M , ATIC
I : AUTO - PUVB
The diagonally opposite element is substituted by its immediate following alphabet in the English alphabetical series.
=> A is substituted by B at its diagonally opposite position. Similarly, U is substituted by V at its diagonally opposite position and similarly T & O by U and P.
II : M - M
The middle letter is used as it is.
III : ATIC - BUJD
The opposite (not diagonally) element is substituted by its immediate following alphabet in the English alphabetical series.
=> A is substituted by B at its opposite position. Similarly T is substituted by U at its opposite position and similarly I & C by J and D.
Thus, code for BUILDINGS :
BUIL - MJVC
D - D
INGS - JOHT
$\therefore$ BUILDINGS - MJVCDJOHT